Syntax
int
stripos ( string haystack, string needle [, int offset] )
Returns the numeric position of the first occurrence of
needle in the haystack
string. Unlike strpos(),
stripos() is case-insensitive.
Note that the needle may be a string of one or
more characters.
If needle is not found,
stripos() will return boolean FALSE.
| Warning |
This function may
return Boolean FALSE, but may also return a non-Boolean value which
evaluates to FALSE, such as 0 or
"". Please read the section on Booleans for more
information. Use the ===
operator for testing the return value of this
function. |
Example 1. stripos() examples
<?php
$findme = 'a';
$mystring1 = 'xyz';
$mystring2 = 'ABC';
$pos1 = stripos($mystring1, $findme);
$pos2 = stripos($mystring2, $findme);
// Nope, 'a' is certainly not in 'xyz'
if ($pos1 === false) {
echo "The string '$findme' was not found in the string '$mystring1'";
}
// Note our use of ===. Simply == would not work as expected
// because the position of 'a' is the 0th (first) character.
if ($pos2 !== false) {
echo "We found '$findme' in '$mystring2' at position $pos2";
}
?>
|
|
If needle is not a string, it is converted
to an integer and applied as the ordinal value of a character.
The optional offset parameter allows you
to specify which character in haystack to
start searching. The position returned is still relative to the
the beginning of haystack.
Note: This function is
binary-safe.
See also strpos(), strrpos(),
strrchr(), substr(),
stristr(), strstr(),
strripos() and str_ireplace().